5x^2-401x+80=0

Solution for 5x^2-401x+80=0 equation:

Simplifying
5x2 + -401x + 80 = 0

Reorder the terms:
80 + -401x + 5x2 = 0

Solving
80 + -401x + 5x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(1 + -5x)(80 + -1x) = 0

Subproblem 1
Set the factor '(1 + -5x)' equal to zero and attempt to solve:

Simplifying
1 + -5x = 0

Solving
1 + -5x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -5x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -5x = 0 + -1
-5x = 0 + -1

Combine like terms: 0 + -1 = -1
-5x = -1

Divide each side by '-5'.
x = 0.2

Simplifying
x = 0.2
Subproblem 2
Set the factor '(80 + -1x)' equal to zero and attempt to solve:

Simplifying
80 + -1x = 0

Solving
80 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-80' to each side of the equation.
80 + -80 + -1x = 0 + -80

Combine like terms: 80 + -80 = 0
0 + -1x = 0 + -80
-1x = 0 + -80

Combine like terms: 0 + -80 = -80
-1x = -80

Divide each side by '-1'.
x = 80

Simplifying
x = 80
Solution
x = {0.2, 80}